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Lesson 8 min

From words to equations

Turn a situation into an equation or inequality, then solve and interpret.

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From words to math

Everything in this course has been about solving equations someone handed you. In real problems you have to write the equation yourself. The trick is to play with the situation first and notice the pattern, then write the pattern down.

Build it before you write it

A gym charges a $20 sign-up fee plus $15 per month. After how many months will you have paid $110?

Add months one at a time and watch the total.

20
$20
target $110
20+15⋅0=2020 + 15 \cdot 0 = 20$90 to go.
0 months

Every month adds another 1515 on top of the starting 2020. After mm months, that's 20+15m20 + 15m. You want that to be 110110, so the equation is:

1

20+15m=11020 + 15m = 110

Clicking found the answer here, but it would take a long time for a total of $11,000. The equation is just as fast either way.

A routine that works

  1. Name the unknown. Pick a letter and say what it stands for.
  2. Translate. Turn the sentences into an equation or inequality. Trying a few numbers first helps you see the pattern.
  3. Solve it.
  4. Answer the question in words, and check that it makes sense.
WordsMath
55 more than a numberx+5x + 5
55 less than a numberx−5x - 5
twice a number2x2x
a number split into 44 equal partsx4\frac{x}{4}
is, equals, is the same as==
at least, no less than≥\geq
at most, no more than≤\leq

Comparing two plans

Plan A costs $40 plus $5 per class. Plan B costs $10 per class with no fee. After how many classes do they cost the same?

Plan A starts ahead but grows slowly. Plan B starts at zero but grows fast. Watch Plan B catch up.

Plan A
40
$40
Plan B
$0
Plan A: 40+5⋅0=4040 + 5 \cdot 0 = 40Plan B: 10⋅0=010 \cdot 0 = 0Plan B is cheaper after 0 class.
0 class

Let cc be the number of classes. "Cost the same" means the two expressions are equal:

1

40+5c=10c40 + 5c = 10c

Both plans cost $80 at 8 classes. After that, Plan A is the better deal.

Inequalities: "at most" and "at least"

You have $50. Movie tickets cost $12 each and you'll spend $8 on snacks. How many tickets can you buy?

8
$8
budget $50
8+12⋅0=88 + 12 \cdot 0 = 8$8 fits the $50 budget, with $42 to spare.
0 tickets

Let tt be the number of tickets. You can spend at most $50, so this is an inequality:

1

12t+8≤5012t + 8 \leq 50

You can't buy half a ticket, so the answer is at most 3 tickets. Interpreting the answer matters: the math says 3.53.5, but the situation says 33.

Consecutive numbers

Three consecutive whole numbers add to 5757. What are they?

If the first is nn, the next two are n+1n + 1 and n+2n + 2.

1

n+(n+1)+(n+2)=57n + (n + 1) + (n + 2) = 57

The numbers are 1818, 1919 and 2020. Sanity check: 57÷3=1957 \div 3 = 19, the middle number.

Quick check

A taxi charges $3 plus $2 per mile. A ride cost $17. How many miles was it?

Key ideas

  • Play with the situation first: a few concrete numbers reveal the pattern.
  • Name the unknown, then translate piece by piece: "is" is ==, "at least" is ≥\geq, "at most" is ≤\leq.
  • Answer the question that was asked, and make sure the answer fits the situation.